There’s a good way to throw out the ISS. And then there’s a really bad way.
思路:找「右侧第一个 ≤ cur」的元素 → 弹出所有 cur 的元素,栈顶即为折扣。最终价格 = cur - 折扣(有则)或 cur(无则)。
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10 February 2026ShareSave
Tourette's film nominated for six BAFTA awards
Examples: The samples directory has working code for common patterns